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Mr Brewin’s Y12 – C1 – Sequences

Here’s the slides from the lesson. Ex 6F please for Weds!

 

11 comments to Mr Brewin’s Y12 – C1 – Sequences

  • DEXTER

    Hi,

    With Calculus/Differentiation,

    e.g. f(x) = x3 – 9×2 + 24x + 20

    i know that u can differentiate that to
    >> f’(x) = 3×2-18x+24

    but can one keep differentiating it down to
    >> f’(x) = 6x-18 ???? or can u only differentiate once?

  • Hi Deola,

    No, you can differentate more than once. The first derivative gives you the gradient ie how the function is changing with x. The second derivative tells you how the gradient is changing with x, and thus it is used to work out whether a turning point is a max or min.

    Mrs T

  • Mariam

    in one of the past papers part of a question is: show that k satisfies (3k-100)(k+35), which i’ve done, but i can’t seem to get the next bit- find the value of k.
    The answer says its 100/3 so k=33 but i dont know where these numbers have come from…. help please

  • Hi Mariam,
    There must be some info somewhere in the question which will enable you to turn this expression into an equation. You can’t solve for k without an equation.
    If you can’t find it, you’ll need to give me the paper details or type out the question.
    Have fun,
    Mrs T

  • Mariam

    Ive got the equation 3k^2+5k-3500<0
    its from the paper- 10 January 2007- afternoon
    reference :6663/01
    I hope thats helpful, and thanks for helping :)

  • Mr Brewin

    OK… So it looks like that’ll go to:

    $latex (x – 33\frac{1}{3})(x +35) \latex$

    Thanks to http://www.math.com/students/calculators/source/quadratic.htm

  • Mr Brewin

    Ooops… Latex not working in comments.

    (k – 33 1/3) ( k + 35)
    ;-)

  • Mariam

    oh rite, i think i get it now, thanks sir

  • Mariam

    for the january stats exam, we only have to revise up to 5.3 rite, the addition rule???

  • Bernice

    how do you prove that Sn=1/2n (2a+(n-1)d) using gauss’ method????

  • Mr Brewin

    It’s right there in the text book. You start with a + (a + d) + (a + 2d)… up to (a + (n-1)d) then you reverse it, and subtract… Enough to go on?

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