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	<title>Comments on: Mr Brewin&#8217;s Y12 &#8211; C1 &#8211; Sequences</title>
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	<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/</link>
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		<title>By: Mr Brewin</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4706</link>
		<dc:creator>Mr Brewin</dc:creator>
		<pubDate>Wed, 07 Jan 2009 22:02:31 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4706</guid>
		<description>It&#039;s right there in the text book. You start with a + (a + d) + (a + 2d)...  up to (a + (n-1)d) then you reverse it, and subtract... Enough to go on?</description>
		<content:encoded><![CDATA[<p>It&#8217;s right there in the text book. You start with a + (a + d) + (a + 2d)&#8230;  up to (a + (n-1)d) then you reverse it, and subtract&#8230; Enough to go on?</p>
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		<title>By: Bernice</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4705</link>
		<dc:creator>Bernice</dc:creator>
		<pubDate>Wed, 07 Jan 2009 21:27:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4705</guid>
		<description>how do you prove that Sn=1/2n (2a+(n-1)d)  using gauss&#039; method????</description>
		<content:encoded><![CDATA[<p>how do you prove that Sn=1/2n (2a+(n-1)d)  using gauss&#8217; method????</p>
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	<item>
		<title>By: Mariam</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4704</link>
		<dc:creator>Mariam</dc:creator>
		<pubDate>Tue, 30 Dec 2008 19:46:15 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4704</guid>
		<description>for the january stats exam, we only have to revise up to 5.3 rite,  the addition rule???</description>
		<content:encoded><![CDATA[<p>for the january stats exam, we only have to revise up to 5.3 rite,  the addition rule???</p>
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	</item>
	<item>
		<title>By: Mariam</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4703</link>
		<dc:creator>Mariam</dc:creator>
		<pubDate>Mon, 29 Dec 2008 19:10:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4703</guid>
		<description>oh rite, i think i get it now, thanks sir</description>
		<content:encoded><![CDATA[<p>oh rite, i think i get it now, thanks sir</p>
]]></content:encoded>
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	<item>
		<title>By: Mr Brewin</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4702</link>
		<dc:creator>Mr Brewin</dc:creator>
		<pubDate>Mon, 29 Dec 2008 18:49:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4702</guid>
		<description>Ooops... Latex not working in comments.

(k - 33 1/3) ( k + 35)

;-)</description>
		<content:encoded><![CDATA[<p>Ooops&#8230; Latex not working in comments.</p>
<p>(k &#8211; 33 1/3) ( k + 35)<br />
 <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' /> </p>
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	<item>
		<title>By: Mr Brewin</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4701</link>
		<dc:creator>Mr Brewin</dc:creator>
		<pubDate>Mon, 29 Dec 2008 18:49:05 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4701</guid>
		<description>OK... So it looks like that&#039;ll go to:

$latex (x - 33\frac{1}{3})(x +35) \latex$

Thanks to http://www.math.com/students/calculators/source/quadratic.htm</description>
		<content:encoded><![CDATA[<p>OK&#8230; So it looks like that&#8217;ll go to:</p>
<p>$latex (x &#8211; 33\frac{1}{3})(x +35) \latex$</p>
<p>Thanks to <a href="http://www.math.com/students/calculators/source/quadratic.htm" rel="nofollow">http://www.math.com/students/calculators/source/quadratic.htm</a></p>
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	<item>
		<title>By: Mariam</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4700</link>
		<dc:creator>Mariam</dc:creator>
		<pubDate>Mon, 29 Dec 2008 15:25:35 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4700</guid>
		<description>Ive got the equation 3k^2+5k-3500&lt;0
its from the paper- 10 January 2007- afternoon
reference :6663/01
I hope thats helpful, and thanks for helping :)</description>
		<content:encoded><![CDATA[<p>Ive got the equation 3k^2+5k-3500&lt;0<br />
its from the paper- 10 January 2007- afternoon<br />
reference :6663/01<br />
I hope thats helpful, and thanks for helping <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4699</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sat, 27 Dec 2008 18:00:02 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4699</guid>
		<description>Hi Mariam,
There must be some info somewhere in the question which will enable you to turn this expression into an equation. You can&#039;t solve for k without an equation.
If you can&#039;t find it, you&#039;ll need to give me the paper details or type out the question.
Have fun,
Mrs T</description>
		<content:encoded><![CDATA[<p>Hi Mariam,<br />
There must be some info somewhere in the question which will enable you to turn this expression into an equation. You can&#8217;t solve for k without an equation.<br />
If you can&#8217;t find it, you&#8217;ll need to give me the paper details or type out the question.<br />
Have fun,<br />
Mrs T</p>
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	</item>
	<item>
		<title>By: Mariam</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4698</link>
		<dc:creator>Mariam</dc:creator>
		<pubDate>Sat, 27 Dec 2008 15:04:57 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4698</guid>
		<description>in one of the past papers part of a question is: show that k satisfies (3k-100)(k+35), which i&#039;ve done, but i can&#039;t seem to get the next bit- find the value of k.
The answer says its 100/3 so k=33 but i dont know where these numbers have come from.... help please</description>
		<content:encoded><![CDATA[<p>in one of the past papers part of a question is: show that k satisfies (3k-100)(k+35), which i&#8217;ve done, but i can&#8217;t seem to get the next bit- find the value of k.<br />
The answer says its 100/3 so k=33 but i dont know where these numbers have come from&#8230;. help please</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/2008/11/mr-brewins-y12-c1-sequences/comment-page-1/#comment-4697</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 19 Nov 2008 18:39:48 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1039#comment-4697</guid>
		<description>Hi Deola,

No, you can differentate more than once. The first derivative gives you the gradient ie how the function is changing with x. The second derivative tells you how the gradient is changing with x, and thus it is used to work out whether a turning point is a max or min.

Mrs T</description>
		<content:encoded><![CDATA[<p>Hi Deola,</p>
<p>No, you can differentate more than once. The first derivative gives you the gradient ie how the function is changing with x. The second derivative tells you how the gradient is changing with x, and thus it is used to work out whether a turning point is a max or min.</p>
<p>Mrs T</p>
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