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	<title>Comments on: Mr Brewin&#8217;s Year 12 Stats</title>
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		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4951</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sun, 17 May 2009 20:37:55 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4951</guid>
		<description>Hi Celia,
Yes, add 1 before dividing by 2 or 4.
If you get .5, go halfway between the numbers each side of it.
If you get .25, go 1/4 of the way up the difference.
If you get .75, go 3/4 of the way up the gap.
Hope that makes sense!
Mr W is doing some S1 revision with the year 13 retakes tomorrow, so if you&#039;re around feel free to pop in.
JT</description>
		<content:encoded><![CDATA[<p>Hi Celia,<br />
Yes, add 1 before dividing by 2 or 4.<br />
If you get .5, go halfway between the numbers each side of it.<br />
If you get .25, go 1/4 of the way up the difference.<br />
If you get .75, go 3/4 of the way up the gap.<br />
Hope that makes sense!<br />
Mr W is doing some S1 revision with the year 13 retakes tomorrow, so if you&#8217;re around feel free to pop in.<br />
JT</p>
]]></content:encoded>
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	<item>
		<title>By: Celia</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4950</link>
		<dc:creator>Celia</dc:creator>
		<pubDate>Sun, 17 May 2009 20:31:38 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4950</guid>
		<description>My final question or least I hope.

When dealing with median  should you always add one and divide by 2. And if it is a even number adding one and dividing by 2 you get a .5 number so you add the number either side.

when dealing with the continuous data and doing interpolating and you have an even number should you use the .5 number or use the number you would get if you simpley divided by 2.


Finally for the upper and lower quartiles add one and divide by four (then times 3 for UQ). you get. 25. do you round up or down or do you add the numbers found to either side of the .25 area and divide by 2. same for continuous should you add one ?

Thank you Mrs Tibble been a big help this weekend sorting out the easy but for some reason bothering me bits .

Celia</description>
		<content:encoded><![CDATA[<p>My final question or least I hope.</p>
<p>When dealing with median  should you always add one and divide by 2. And if it is a even number adding one and dividing by 2 you get a .5 number so you add the number either side.</p>
<p>when dealing with the continuous data and doing interpolating and you have an even number should you use the .5 number or use the number you would get if you simpley divided by 2.</p>
<p>Finally for the upper and lower quartiles add one and divide by four (then times 3 for UQ). you get. 25. do you round up or down or do you add the numbers found to either side of the .25 area and divide by 2. same for continuous should you add one ?</p>
<p>Thank you Mrs Tibble been a big help this weekend sorting out the easy but for some reason bothering me bits .</p>
<p>Celia</p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4949</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sun, 17 May 2009 12:04:03 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4949</guid>
		<description>Hi Celia,
I&#039;ve looked at a mark scheme and it said 3sf or better, so I would go with 3sf in the absence of any guidance.
JT</description>
		<content:encoded><![CDATA[<p>Hi Celia,<br />
I&#8217;ve looked at a mark scheme and it said 3sf or better, so I would go with 3sf in the absence of any guidance.<br />
JT</p>
]]></content:encoded>
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	<item>
		<title>By: Celia</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4948</link>
		<dc:creator>Celia</dc:creator>
		<pubDate>Sun, 17 May 2009 09:22:53 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4948</guid>
		<description>With lines of regression calculations

for the final answer a +bx should a  and b be done to 3sf or 2dp?
Thanks</description>
		<content:encoded><![CDATA[<p>With lines of regression calculations</p>
<p>for the final answer a +bx should a  and b be done to 3sf or 2dp?<br />
Thanks</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4947</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Fri, 15 May 2009 17:36:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4947</guid>
		<description>Yes - cos it&#039;s just change side, change sign for the two terms.</description>
		<content:encoded><![CDATA[<p>Yes &#8211; cos it&#8217;s just change side, change sign for the two terms.</p>
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		<title>By: Celia</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4946</link>
		<dc:creator>Celia</dc:creator>
		<pubDate>Fri, 15 May 2009 17:34:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4946</guid>
		<description>sorry to bother again, for the formula P(A)+P(B)- P(AnB)= P(AuB)

The u one and and n can be switched round?
thanks</description>
		<content:encoded><![CDATA[<p>sorry to bother again, for the formula P(A)+P(B)- P(AnB)= P(AuB)</p>
<p>The u one and and n can be switched round?<br />
thanks</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4945</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Fri, 15 May 2009 17:23:58 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4945</guid>
		<description>Hi Celia,
First letter is a capital.
JT</description>
		<content:encoded><![CDATA[<p>Hi Celia,<br />
First letter is a capital.<br />
JT</p>
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	<item>
		<title>By: Celia</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4944</link>
		<dc:creator>Celia</dc:creator>
		<pubDate>Fri, 15 May 2009 17:10:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4944</guid>
		<description>tried the thing you told Jacynth and couldn&#039;t get in. Has the password been changed?

thanks</description>
		<content:encoded><![CDATA[<p>tried the thing you told Jacynth and couldn&#8217;t get in. Has the password been changed?</p>
<p>thanks</p>
]]></content:encoded>
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	<item>
		<title>By: Celia</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4943</link>
		<dc:creator>Celia</dc:creator>
		<pubDate>Fri, 15 May 2009 17:04:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4943</guid>
		<description>Mr Brewin,

Sorry to bother you but in the stats textbook chp 5 mixed exercise for question 5b. If you did 6 x ×7 /15×3 /14 ×5 /13

or went through the whole tree diagram doing each route then adding together would you get the same answer?

Which way would you suggest?

Thanks</description>
		<content:encoded><![CDATA[<p>Mr Brewin,</p>
<p>Sorry to bother you but in the stats textbook chp 5 mixed exercise for question 5b. If you did 6 x ×7 /15×3 /14 ×5 /13</p>
<p>or went through the whole tree diagram doing each route then adding together would you get the same answer?</p>
<p>Which way would you suggest?</p>
<p>Thanks</p>
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	<item>
		<title>By: Mr Brewin</title>
		<link>http://www.shsmaths.com/2009/03/mr-brewins-year-12-stats-4/comment-page-1/#comment-4942</link>
		<dc:creator>Mr Brewin</dc:creator>
		<pubDate>Wed, 29 Apr 2009 21:06:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?p=1108#comment-4942</guid>
		<description>Err... can&#039;t really say exactly, but what&#039;s the local area our school is in? Try that!</description>
		<content:encoded><![CDATA[<p>Err&#8230; can&#8217;t really say exactly, but what&#8217;s the local area our school is in? Try that!</p>
]]></content:encoded>
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