Comments on: Revision for year 9 http://www.shsmaths.com/2010/01/revision-for-year-9/ Thu, 15 Jul 2010 12:28:59 +0000 hourly 1 http://wordpress.org/?v=3.0 By: Nina http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6460 Nina Sun, 07 Feb 2010 21:19:28 +0000 http://www.shsmaths.com/?p=1464#comment-6460 WHY DO I ALWAYS HAVE A REALLY UGLY PENTAGON! I AM ALSO NOT ALWAYS UNHAPPY! :) <-- SEE! :) WHY DO I ALWAYS HAVE A REALLY UGLY PENTAGON! I AM ALSO NOT ALWAYS UNHAPPY! :) <– SEE! :)

]]> By: Nina http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6459 Nina Sun, 07 Feb 2010 21:18:01 +0000 http://www.shsmaths.com/?p=1464#comment-6459 to me that just sounds like gobbldy goop! :S I know that about 1,000,000 people are stuck on this homework, so it looks like we will spend a long time on it tomorrow.... :) Thank you anyway, Mrs Tibble! :) to me that just sounds like gobbldy goop! :S
I know that about 1,000,000 people are stuck on this homework, so it looks like we will spend a long time on it tomorrow…. :)
Thank you anyway, Mrs Tibble! :)

]]> By: Mrs Tibble http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6458 Mrs Tibble Sun, 07 Feb 2010 20:38:39 +0000 http://www.shsmaths.com/?p=1464#comment-6458 Hi Nina, You need to keep substituting in the values from the graph and then solve what's left of the equation. Equation is h = at^2 + bt + c Part (a) from graph, when t=0, h=0 as well. Put 0 into the eqn for t and h and you'll get 0=c, therefore c=0 This means equation only has 2 terms because you can drop c. When t=5 on graph, h=0 again. Plug that into the equation. That will give you an equation that you can't solve because it has both a and b in it. Do the same with t=1 now, getting the h value off the graph. Now you'll have a pair of simultaneous equations which you can solve to get a and b. Have fun ;-) JT (the reliable one!!) Hi Nina,

You need to keep substituting in the values from the graph and then solve what’s left of the equation.
Equation is
h = at^2 + bt + c

Part (a) from graph, when t=0, h=0 as well. Put 0 into the eqn for t and h and you’ll get 0=c, therefore c=0
This means equation only has 2 terms because you can drop c.
When t=5 on graph, h=0 again. Plug that into the equation. That will give you an equation that you can’t solve because it has both a and b in it.
Do the same with t=1 now, getting the h value off the graph.
Now you’ll have a pair of simultaneous equations which you can solve to get a and b.

Have fun ;-)
JT (the reliable one!!)

]]> By: Mr Brewin http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6457 Mr Brewin Sun, 07 Feb 2010 20:23:01 +0000 http://www.shsmaths.com/?p=1464#comment-6457 Sorry -can't for the life of me find my 9A book here at home! Don't worry - noted that you've tried it. We'll go over it tomorrow, or come and find me. KB Sorry -can’t for the life of me find my 9A book here at home! Don’t worry – noted that you’ve tried it. We’ll go over it tomorrow, or come and find me.

KB

]]> By: Nina http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6456 Nina Sun, 07 Feb 2010 20:01:36 +0000 http://www.shsmaths.com/?p=1464#comment-6456 no we didnt, just Q4 + 5! only.... ;) no we didnt, just Q4 + 5! only…. ;)

]]> By: Pia http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6455 Pia Sun, 07 Feb 2010 19:14:30 +0000 http://www.shsmaths.com/?p=1464#comment-6455 Pina... did we have to do q6... I'm stuck on 4 too :'( Pina… did we have to do q6… I’m stuck on 4 too :’(

]]> By: Nina http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6454 Nina Sun, 07 Feb 2010 19:02:21 +0000 http://www.shsmaths.com/?p=1464#comment-6454 I am very sorry, but i cannot do Q4 of the maths homework. I have done Q5 - but i do not understand how to work out Q4 at all! :( I have left a note on the maths blog, but nobody has been online and no-one seems to be onine/have their phone on so no-one could explain it to me! :( Nina I am very sorry, but i cannot do Q4 of the maths homework. I have done Q5 – but i do not understand how to work out Q4 at all! :(
I have left a note on the maths blog, but nobody has been online and no-one seems to be onine/have their phone on so no-one could explain it to me! :(

Nina

]]> By: Nina http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6453 Nina Sun, 07 Feb 2010 16:14:40 +0000 http://www.shsmaths.com/?p=1464#comment-6453 um, q4 page 259 we did a in class, but i dont get the rest! :'( um, q4 page 259
we did a in class, but i dont get the rest! :’(

]]> By: Mrs Tibble http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6452 Mrs Tibble Sun, 07 Feb 2010 15:53:35 +0000 http://www.shsmaths.com/?p=1464#comment-6452 What do you have to do? What do you have to do?

]]> By: Nina http://www.shsmaths.com/2010/01/revision-for-year-9/comment-page-1/#comment-6451 Nina Sun, 07 Feb 2010 14:34:21 +0000 http://www.shsmaths.com/?p=1464#comment-6451 Please can someone help me with the maths homework! :) Please can someone help me with the maths homework! :)

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