In addition to the paper I gave you, can you also do this one please. Have a good holiday!
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Mr Brewin’s Y11 – Past Paper for EasterIn addition to the paper I gave you, can you also do this one please. Have a good holiday! 3 comments to Mr Brewin’s Y11 – Past Paper for Easter |
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Sir im doing some revision on solving equations and i can’t answer the fraction equation:
3x+9/3 – 2x+4/5 = 4
Please can you explain how to answer this question?
Hi Lily,
Are those dividing lines under two terms? ie is it
(3x + 9)/3 – (2x + 4)/5 = 4
If so, multiply every term by 15 to get rid of the denominators, then solve in the normal way.
JT
Yeah, what she said
15 is LCM of 3 and 5, so it becomes [15 * (3x+9) / 3] – [15 * (2x +4)5] = 60
And that will then go to 5(3x+9) – 3(2x+4) = 60
OK?