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Sixth FormFor general help, just shout here using the comments box below. 3 comments to Sixth Form |
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Hello!
Show that e^(0.8x)- (1/3-2x)= 0 can be written as x = 1.5 – 0.5e^(-0.8x)
I know I should be able to rearrange that.. but for some reason I can’t!
Can you give me a nudge?
Happy Christmas!
Grace.
OK, so if you take the 1/(3-2x) over… then do the reciprocal of that, you should end up with
3 – 2x = e^(-0.8x)
Then should be able to do it from there?
Well done revising Christmas Eve! Hope you take a break now!
After another 20 minutes of wobbling it around I see, yes.
(just to be sure, you take the 2 out of 3-2x to give 0.5e^-0.8x = 1.5 – x then you’re at the answer after a bit of shuffling, right?)
Wow. Hope I’m not that slow in the exam!
Once I realised it was Christmas Eve I didn’t expect a reply at all – So thanks for helping!
Have a Great Christmas!