Comments on: Sixth Form http://www.shsmaths.com Thu, 15 Jul 2010 12:28:59 +0000 hourly 1 http://wordpress.org/?v=3.0 By: Grace Mullally http://www.shsmaths.com/get-help/sixth-form/comment-page-1/#comment-6130 Grace Mullally Thu, 24 Dec 2009 19:40:27 +0000 http://www.shsmaths.com/?page_id=1227#comment-6130 After another 20 minutes of wobbling it around I see, yes. (just to be sure, you take the 2 out of 3-2x to give 0.5e^-0.8x = 1.5 - x then you're at the answer after a bit of shuffling, right?) Wow. Hope I'm not that slow in the exam! Once I realised it was Christmas Eve I didn't expect a reply at all - So thanks for helping! Have a Great Christmas! After another 20 minutes of wobbling it around I see, yes.

(just to be sure, you take the 2 out of 3-2x to give 0.5e^-0.8x = 1.5 – x then you’re at the answer after a bit of shuffling, right?)

Wow. Hope I’m not that slow in the exam!

Once I realised it was Christmas Eve I didn’t expect a reply at all – So thanks for helping!

Have a Great Christmas!

]]> By: Mr Brewin http://www.shsmaths.com/get-help/sixth-form/comment-page-1/#comment-6129 Mr Brewin Thu, 24 Dec 2009 16:48:14 +0000 http://www.shsmaths.com/?page_id=1227#comment-6129 OK, so if you take the 1/(3-2x) over... then do the reciprocal of that, you should end up with 3 - 2x = e^(-0.8x) Then should be able to do it from there? Well done revising Christmas Eve! Hope you take a break now! OK, so if you take the 1/(3-2x) over… then do the reciprocal of that, you should end up with
3 – 2x = e^(-0.8x)

Then should be able to do it from there?

Well done revising Christmas Eve! Hope you take a break now!

]]> By: Grace Mullally http://www.shsmaths.com/get-help/sixth-form/comment-page-1/#comment-6128 Grace Mullally Thu, 24 Dec 2009 15:12:20 +0000 http://www.shsmaths.com/?page_id=1227#comment-6128 Hello! Show that e^(0.8x)- (1/3-2x)= 0 can be written as x = 1.5 - 0.5e^(-0.8x) I know I should be able to rearrange that.. but for some reason I can't! Can you give me a nudge? Happy Christmas! Grace. Hello!

Show that e^(0.8x)- (1/3-2x)= 0 can be written as x = 1.5 – 0.5e^(-0.8x)

I know I should be able to rearrange that.. but for some reason I can’t!
Can you give me a nudge?

Happy Christmas!

Grace.

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