Shout here for any general help on Pure Maths stuff from Y12 or Y13…
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Pure Maths28 comments to Pure Maths |
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Copyright © 2010 The Sydenham High School Mathematics Department Blog - All Rights Reserved |
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Pure MathsShout here for any general help on Pure Maths stuff from Y12 or Y13… 28 comments to Pure Maths |
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Copyright © 2010 The Sydenham High School Mathematics Department Blog - All Rights Reserved |
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I can’t do 7f, 16aiii and 16b! I’ve gone through a million different ways and still don’t know what to do.
Hi Deola,
16a part iii
The tan of 45deg is 1 so you can replace some of the 1s with tan45 to get the format of tan(A-B)
16b
Start by expanding the bracket on the right and using the values you know for cos and sin 60. See where that leads.
Tea Lady
thanx
next question?
how do you find the maximum when it involves sin, because i can do it with cos, as cos(0)=1 or something like that
Hi Deola,
Think about the sine curve: max value of sine = 1, min value = -1
i’m stuck on two questions, i thought i could do them but i cant get the answer and i don’t know why
1.given that cotx = -1.5 and that x is obtuse, find the exact value of cosecx
i can get the value right, but i cant get the sign right, in the answers it says cosecx = – (root 13)/ 2, but if its obtuse and tan is negative it has to be in the second quadrant and therefore shouldn’t sinx be positive?
2. find the exact value of cos(arcsin(-1/3)) -pie/2 (< and equal to) arcsinx (< and equal to) pie/2
when i did it i got root 2/3 but the answer says 2root2/3, i'm confused
also does (tan-b)=tanb?
megan
Hi Megan,
I agree with you on the first one.
Last bit: tan(-b) = – tan b.
I’ll come back on the other one when I’ve worked it out!
JT
Hi Megan,
Do your Pythagoras triangle: sine is 1 over 3 which makes the third side root8. Root 8 is 2root3.
JT
thankyou
i’m getting kind of confused with inverse’s
when you have arcsin (-1/3) doesnt that equal pie/6
when you have cos/tan/sin with arc does that go to the angle or the side as in is it like pie/4 or like 1/3? if that makes sense lol
also my calculator broke today, so i got a new one, but because i’m not that used to it, do you have an old style one that i could take in the exam aswell incase i cant work out how to do something on the newer one?
Hi Megan, don’t confuse 1/3 with 1/root3 which is the TAN of 30deg.
Remember, you can always check them on your calculator – does it do surd form?
The answer to arc-anything is an angle.
eg arcsin0.5
Read it as ‘the angle whose sine is 0.5′
Yes, you can borrow my calculator.
JT
thanks that helps alot.
where will you be around 12.30, 1ish, so i can come get the calculator?
With a combined function fg(x) how do you know the domain of x or the range? Are you supposed to know?
In one question, for f(x) x was bigger than 1, but in g(x) x was an element of the real numbers. Then what is the domain for fg(x)?
Thanks
Megan – depends if any year 13s are around. C7 or lunch!!
Emily, the range of the function you do first becomes the domain for the second function.
Ok so in fg(x) the range of g(x) becomes the domain for fg(x)?
thanks see you tommorow
sorry last question, when you do the change of sign rule does it have to be in radians?
Emily – yes.
Megan – have no idea what you’re talking about lol! Ask me tomorrow – go to bed now!
thank you
i cant do question 2 in the ex5k.
Hi Deola,
Do you have my C4? The one you asked me for for Mr Atkins?
You have a and b (sorry can’t bold or underline them)
so you can find vector AB = b – a
Double that to get vector AP
then AP = p – a
JT
omg!! lol sorry mrs T that’s what i was meant to say when i left my first message. I completely forgot to see mr Atkins after i left your classroom.
why do u need to double AB because AP is double BP?
Also their answer was (-i-2j-5k)?
ALSO, i dont know how to go about question 4?
Deola, draw it! If you draw AB then keep going till AP is double BP, then B is the midpoint of your line.
You need to find p not AP so are you ATQing?
Q4 How do you find the mod of a vector? Square both sides and you’re there.
Good job I managed to find a spare C4 in school today then, wasn’t it?!!
JT
i drew it and AP was 2/3 of AB. The problem is that i dont understand any of these questions tbh.
But i still don’t understand because i don’t know how to use the position vectors they have given.
q4….but they asked for the point of intersection so don’t i need to create 2 vector equations?
Deola,
Q2 RTQ It says P is on AB produced ie extended, not AB itself.
Q4 Sorry – was looking at wrong exercise.
You need the vectors of the 2 lines
Call points A B C D for example
then AB = b – a
CD = d – c
then you can do their dot product to find the angle between them.
The vectors AB and CD will be your direction vectors for finding the point of intersection. See example 33.
i didnt know that produced meant extened sorry
okay i’ll try q4 again and see how it goes
yet again im stuck, i cant do part 2 of q7?
Find vector AB
AC is 2/3 of that
AC = c-a
I think you need to revise position vectors, in particular the general result that
vector PQ = q-p
Going out now so you’re on your own till later tonight.