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	<title>Comments on: Pure Maths</title>
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		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6674</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Mon, 22 Mar 2010 20:41:56 +0000</pubDate>
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		<description>Hi Mel,
OK. Will bring my C3 book then.
JT</description>
		<content:encoded><![CDATA[<p>Hi Mel,<br />
OK. Will bring my C3 book then.<br />
JT</p>
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		<title>By: Mel Cagacar</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6673</link>
		<dc:creator>Mel Cagacar</dc:creator>
		<pubDate>Mon, 22 Mar 2010 19:40:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6673</guid>
		<description>Hey Mrs Tibble
Was wondering if it&#039;d be ok to look at some questions from C3 Ex6F tomorrow? 
Thank you</description>
		<content:encoded><![CDATA[<p>Hey Mrs Tibble<br />
Was wondering if it&#8217;d be ok to look at some questions from C3 Ex6F tomorrow?<br />
Thank you</p>
]]></content:encoded>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6672</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sun, 21 Mar 2010 16:21:30 +0000</pubDate>
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		<description>NOOOOOOOOOOOOO!
Integrate them separately.

Whenever you wonder about something like that, try putting in some numbers eg does cos75cos25 = cos90?</description>
		<content:encoded><![CDATA[<p>NOOOOOOOOOOOOO!<br />
Integrate them separately.</p>
<p>Whenever you wonder about something like that, try putting in some numbers eg does cos75cos25 = cos90?</p>
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		<title>By: Megan Conway</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6671</link>
		<dc:creator>Megan Conway</dc:creator>
		<pubDate>Sun, 21 Mar 2010 16:12:13 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6671</guid>
		<description>o i get it Thankyou.
you cant add cos3x and cosx to get cos4x can you? 

megan</description>
		<content:encoded><![CDATA[<p>o i get it Thankyou.<br />
you cant add cos3x and cosx to get cos4x can you? </p>
<p>megan</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6670</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sun, 21 Mar 2010 13:12:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6670</guid>
		<description>Hi Megan,
Have you found it?
It&#039;s the format for the sum of two cosines.
To get the first one, add your angles; to get the second one, subtract.

Therefore 2 cos2x cosx = cos(2x+x) + cos(2x-x) = cos3x + cosx
and these are functions which you know how to integrate.
JT</description>
		<content:encoded><![CDATA[<p>Hi Megan,<br />
Have you found it?<br />
It&#8217;s the format for the sum of two cosines.<br />
To get the first one, add your angles; to get the second one, subtract.</p>
<p>Therefore 2 cos2x cosx = cos(2x+x) + cos(2x-x) = cos3x + cosx<br />
and these are functions which you know how to integrate.<br />
JT</p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6669</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Fri, 19 Mar 2010 23:07:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6669</guid>
		<description>Hi Megan,

It&#039;s one of those P+Q, P-Q thingies!
Have a look at the trig in your C3 notes for the one with the cos cos format.
Good luck
:-)</description>
		<content:encoded><![CDATA[<p>Hi Megan,</p>
<p>It&#8217;s one of those P+Q, P-Q thingies!<br />
Have a look at the trig in your C3 notes for the one with the cos cos format.<br />
Good luck<br />
 <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_smile.gif' alt=':-)' class='wp-smiley' /> </p>
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		<title>By: Megan Conway</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6668</link>
		<dc:creator>Megan Conway</dc:creator>
		<pubDate>Fri, 19 Mar 2010 20:39:54 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6668</guid>
		<description>i&#039;m stuck on ex6c 3a - how do you intergrate cos2xcosx? 
megan</description>
		<content:encoded><![CDATA[<p>i&#8217;m stuck on ex6c 3a &#8211; how do you intergrate cos2xcosx?<br />
megan</p>
]]></content:encoded>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6559</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 17 Feb 2010 17:27:13 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6559</guid>
		<description>Find vector AB
AC is 2/3 of that
AC = c-a

I think you need to revise position vectors, in particular the general result that
vector PQ = q-p

Going out now so you&#039;re on your own till later tonight.</description>
		<content:encoded><![CDATA[<p>Find vector AB<br />
AC is 2/3 of that<br />
AC = c-a</p>
<p>I think you need to revise position vectors, in particular the general result that<br />
vector PQ = q-p</p>
<p>Going out now so you&#8217;re on your own till later tonight.</p>
]]></content:encoded>
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	<item>
		<title>By: DEOLA</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6558</link>
		<dc:creator>DEOLA</dc:creator>
		<pubDate>Wed, 17 Feb 2010 17:24:19 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1270#comment-6558</guid>
		<description>i didnt know that produced meant extened sorry
okay i&#039;ll try q4 again and see how it goes :(

yet again im stuck, i cant do part 2 of q7?</description>
		<content:encoded><![CDATA[<p>i didnt know that produced meant extened sorry<br />
okay i&#8217;ll try q4 again and see how it goes <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_sad.gif' alt=':(' class='wp-smiley' /> </p>
<p>yet again im stuck, i cant do part 2 of q7?</p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/sixth-form/pure-maths/comment-page-1/#comment-6557</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 17 Feb 2010 17:13:38 +0000</pubDate>
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		<description>The vectors AB and CD will be your direction vectors for finding the point of intersection. See example 33.</description>
		<content:encoded><![CDATA[<p>The vectors AB and CD will be your direction vectors for finding the point of intersection. See example 33.</p>
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