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	<title>Comments on: Mrs Tibble&#8217;s Year 10</title>
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	<item>
		<title>By: Charlotte</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9246</link>
		<dc:creator>Charlotte</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:35:06 +0000</pubDate>
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		<description>ooo right ok thank you! i will give it another go now :)</description>
		<content:encoded><![CDATA[<p>ooo right ok thank you! i will give it another go now <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9245</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:28:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9245</guid>
		<description>Hi Charlotte,

First mistake is in line 1

denominator is 2a which is 4 not 6

Second mistake is in line 3:

16 - 8 isn&#039;t 24

Also, when you do the square-rooting, don&#039;t expect nice numbers. That&#039;s why it says give your answers correct to 2dp.

Good luck!</description>
		<content:encoded><![CDATA[<p>Hi Charlotte,</p>
<p>First mistake is in line 1</p>
<p>denominator is 2a which is 4 not 6</p>
<p>Second mistake is in line 3:</p>
<p>16 &#8211; 8 isn&#8217;t 24</p>
<p>Also, when you do the square-rooting, don&#8217;t expect nice numbers. That&#8217;s why it says give your answers correct to 2dp.</p>
<p>Good luck!</p>
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	<item>
		<title>By: Charlotte</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9244</link>
		<dc:creator>Charlotte</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:23:19 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9244</guid>
		<description>2X squared + 4x + 1=0
a=2
b=4
c=1
x=-b +/- (square root) b squared - 4ac
--------------------------------------
                6
x=-4 +/- (square root) 16-4 X 2 X 1 
-----------------------------------
                 6
x=-4 +/- (square root) 24
---------------------------
                 6
but you cant square root 24..</description>
		<content:encoded><![CDATA[<p>2X squared + 4x + 1=0<br />
a=2<br />
b=4<br />
c=1<br />
x=-b +/- (square root) b squared &#8211; 4ac<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<br />
                6<br />
x=-4 +/- (square root) 16-4 X 2 X 1<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<br />
                 6<br />
x=-4 +/- (square root) 24<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
                 6<br />
but you cant square root 24..</p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9243</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:19:57 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9243</guid>
		<description>From answer book:

Q2. -0.29, -1.71

Q5. -0.57, -1.77

Q8. 2.16, -4.16</description>
		<content:encoded><![CDATA[<p>From answer book:</p>
<p>Q2. -0.29, -1.71</p>
<p>Q5. -0.57, -1.77</p>
<p>Q8. 2.16, -4.16</p>
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	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9242</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:17:03 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9242</guid>
		<description>How do you know your answers are wrong?</description>
		<content:encoded><![CDATA[<p>How do you know your answers are wrong?</p>
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	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9241</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:16:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9241</guid>
		<description>Yes please.</description>
		<content:encoded><![CDATA[<p>Yes please.</p>
]]></content:encoded>
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	<item>
		<title>By: Charlotte</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9240</link>
		<dc:creator>Charlotte</dc:creator>
		<pubDate>Wed, 01 Feb 2012 20:11:51 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9240</guid>
		<description>Hi mrs tibble, i am trying to do the home work, but both of my answers are wrong and i dont know where i am going worng :&#039;( shall i put what i am dong? 
thank you :) charlotte</description>
		<content:encoded><![CDATA[<p>Hi mrs tibble, i am trying to do the home work, but both of my answers are wrong and i dont know where i am going worng :&#8217;( shall i put what i am dong?<br />
thank you <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' />  charlotte</p>
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	<item>
		<title>By: Jasmine</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9236</link>
		<dc:creator>Jasmine</dc:creator>
		<pubDate>Mon, 30 Jan 2012 18:44:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9236</guid>
		<description>Ahhhhh!! that would explain my confusion, thank you! 
and it definitely says +8 in the book</description>
		<content:encoded><![CDATA[<p>Ahhhhh!! that would explain my confusion, thank you!<br />
and it definitely says +8 in the book</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9234</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Mon, 30 Jan 2012 18:40:40 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9234</guid>
		<description>Hi Jasmine,

Are you sure that it says +8?
It would need to be -8 to work.

For x^2 - 7x - 8 = 0
you would get
(x - 8)(x + 1) =0
because -8 x 1 = -8 for the end
and -8 + 1 = -7 for the middle.

If it says +8, it&#039;s wrong!!</description>
		<content:encoded><![CDATA[<p>Hi Jasmine,</p>
<p>Are you sure that it says +8?<br />
It would need to be -8 to work.</p>
<p>For x^2 &#8211; 7x &#8211; 8 = 0<br />
you would get<br />
(x &#8211; 8)(x + 1) =0<br />
because -8 x 1 = -8 for the end<br />
and -8 + 1 = -7 for the middle.</p>
<p>If it says +8, it&#8217;s wrong!!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Jasmine</title>
		<link>http://www.shsmaths.com/get-help/year-10/mrs-tibble/comment-page-5/#comment-9233</link>
		<dc:creator>Jasmine</dc:creator>
		<pubDate>Mon, 30 Jan 2012 18:36:42 +0000</pubDate>
		<guid isPermaLink="false">http://www.shsmaths.com/?page_id=1258#comment-9233</guid>
		<description>Question 15:

xsquared - 7x + 8 = 0

and I have already worked out that the brackets start like this:
(x-   ) (x-   )</description>
		<content:encoded><![CDATA[<p>Question 15:</p>
<p>xsquared &#8211; 7x + 8 = 0</p>
<p>and I have already worked out that the brackets start like this:<br />
(x-   ) (x-   )</p>
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