Comments on: Mr Atkins’ Year 8 http://www.shsmaths.com Thu, 15 Jul 2010 12:28:59 +0000 hourly 1 http://wordpress.org/?v=3.0 By: Mrs Tibble http://www.shsmaths.com/get-help/year-8/mr-atkins/comment-page-1/#comment-6832 Mrs Tibble Sun, 30 May 2010 19:42:19 +0000 http://www.shsmaths.com/?page_id=1235#comment-6832 Hi Kasia, x:9 = 5x:45 (multiplying both by 5) 3:5 = 27:45 (multiplying both by 9) therefore 5x:45 = 27:45 Right hand sides match so lefts must too, so 5x must equal 27 so x = 27/5 which is 5.4 JT Hi Kasia,

x:9 = 5x:45 (multiplying both by 5)

3:5 = 27:45 (multiplying both by 9)

therefore 5x:45 = 27:45
Right hand sides match so lefts must too,
so 5x must equal 27
so x = 27/5 which is 5.4

JT

]]> By: Kasia S http://www.shsmaths.com/get-help/year-8/mr-atkins/comment-page-1/#comment-6830 Kasia S Sun, 30 May 2010 12:40:17 +0000 http://www.shsmaths.com/?page_id=1235#comment-6830 x:9=3:5 How do I find out what x is???? x:9=3:5
How do I find out what x is????

]]> By: Mrs Tibble http://www.shsmaths.com/get-help/year-8/mr-atkins/comment-page-1/#comment-5602 Mrs Tibble Thu, 08 Oct 2009 16:39:51 +0000 http://www.shsmaths.com/?page_id=1235#comment-5602 Hi Megan, You don't need the term-to-term rule because the instructions in the box tell you how to work out the term from its position in the list (the term number) JT Hi Megan,
You don’t need the term-to-term rule because the instructions in the box tell you how to work out the term from its position in the list (the term number)
JT

]]> By: Megan http://www.shsmaths.com/get-help/year-8/mr-atkins/comment-page-1/#comment-5601 Megan Thu, 08 Oct 2009 16:26:13 +0000 http://www.shsmaths.com/?page_id=1235#comment-5601 How do i do the question on page 5 question 4? it doesn't give you the term to term rule :/ How do i do the question on page 5 question 4?
it doesn’t give you the term to term rule :/

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