Comments on: Mrs Tibble’s / Mr Atkins’ Year 9 http://www.shsmaths.com Thu, 15 Jul 2010 12:28:59 +0000 hourly 1 http://wordpress.org/?v=3.0 By: Mrs Tibble http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-6/#comment-6888 Mrs Tibble Sat, 05 Jun 2010 15:40:15 +0000 http://www.shsmaths.com/?page_id=1251#comment-6888 So which year are you? The GCSE link might not be suitable lol So which year are you? The GCSE link might not be suitable lol

]]> By: Claire http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-6/#comment-6887 Claire Sat, 05 Jun 2010 15:19:42 +0000 http://www.shsmaths.com/?page_id=1251#comment-6887 okay thanks! (i didn't know i was on yr9 page sorry) okay thanks! (i didn’t know i was on yr9 page sorry)

]]> By: Mrs Tibble http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-6/#comment-6886 Mrs Tibble Sat, 05 Jun 2010 15:16:50 +0000 http://www.shsmaths.com/?page_id=1251#comment-6886 PS the pictures are nothing to do with us: they are randomly assigned by the site. PS the pictures are nothing to do with us: they are randomly assigned by the site.

]]> By: Mrs Tibble http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6885 Mrs Tibble Sat, 05 Jun 2010 15:15:58 +0000 http://www.shsmaths.com/?page_id=1251#comment-6885 Hi Claire (er do I teach a Claire in year 9?) Which paper is it you are trying to do? If it's the one on here from last year, it won't open for some reason unknown to me. I have passed it up to higher expertise (ie Mr B) but I don't think even he has been able to sort it. You should have been given some practice questions before we broke up, but if not, then try the past GCSE papers online - just pick out the topics from the revision list I did. Here's one: https://eiewebvip.edexcel.org.uk/Reports/Confidential%20Documents/0506/5523_03_que_20050607.pdf JT Hi Claire (er do I teach a Claire in year 9?)
Which paper is it you are trying to do? If it’s the one on here from last year, it won’t open for some reason unknown to me. I have passed it up to higher expertise (ie Mr B) but I don’t think even he has been able to sort it. You should have been given some practice questions before we broke up, but if not, then try the past GCSE papers online – just pick out the topics from the revision list I did.
Here’s one: https://eiewebvip.edexcel.org.uk/Reports/Confidential%20Documents/0506/5523_03_que_20050607.pdf
JT

]]> By: Claire http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6884 Claire Sat, 05 Jun 2010 15:08:52 +0000 http://www.shsmaths.com/?page_id=1251#comment-6884 also, do you choose your profile picture or do you get any automatically? because mine is really weird!!! also, do you choose your profile picture or do you get any automatically? because mine is really weird!!!

]]> By: Claire http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6883 Claire Sat, 05 Jun 2010 15:00:01 +0000 http://www.shsmaths.com/?page_id=1251#comment-6883 HELLO MRS TIBBLE How were your holidays! my computer is not letting me see the mock exam you have got for us, would it be ok if you sent it to me if I gave you an email?? HELLO MRS TIBBLE

How were your holidays! my computer is not letting me see the mock exam you have got for us, would it be ok if you sent it to me if I gave you an email??

]]> By: Mrs Tibble http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6882 Mrs Tibble Sat, 05 Jun 2010 13:31:42 +0000 http://www.shsmaths.com/?page_id=1251#comment-6882 Hi Amelia, the other way you could get the 9 would be to sketch the graph. If the slope is -1/2 then it is a downhill graph, and the y values are dropping in halves. If you start at (4,7) and work back up the slope to the y axis, when you reach x=0, y will have gone up to 9. Hope that helps. JT Hi Amelia,
the other way you could get the 9 would be to sketch the graph. If the slope is -1/2 then it is a downhill graph, and the y values are dropping in halves. If you start at (4,7) and work back up the slope to the y axis, when you reach x=0, y will have gone up to 9.
Hope that helps.
JT

]]> By: Amelia http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6881 Amelia Sat, 05 Jun 2010 09:28:10 +0000 http://www.shsmaths.com/?page_id=1251#comment-6881 Ohhhhhh, thankyou :) Ohhhhhh, thankyou :)

]]> By: Mrs Tibble http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6880 Mrs Tibble Sat, 05 Jun 2010 06:26:24 +0000 http://www.shsmaths.com/?page_id=1251#comment-6880 Hi Amelia, The line y=2x+3 has slope 2 (the m value is the gradient) so a line perpendicular to it will have slope -1/2. This is the m value for line L that you are trying to find. We therefore know now that for L y=-0.5x + c but we don't yet know what the c for this line is. However, we know that the point (4,7) lies on the line so its coordinates must obey the equation of the line. Therefore, substituting in these x and y values gives 7 = -0.5 x 4 + c 7 = -2 + c therefore c = 9 Equation of L is thus y = -0.5x + 9 JT Hi Amelia,
The line y=2x+3 has slope 2 (the m value is the gradient) so a line perpendicular to it will have slope -1/2. This is the m value for line L that you are trying to find.
We therefore know now that for L
y=-0.5x + c
but we don’t yet know what the c for this line is.
However, we know that the point (4,7) lies on the line so its coordinates must obey the equation of the line.
Therefore, substituting in these x and y values gives
7 = -0.5 x 4 + c
7 = -2 + c
therefore c = 9
Equation of L is thus y = -0.5x + 9

JT

]]> By: Amelia http://www.shsmaths.com/get-help/year-9/mrs-tibble/comment-page-5/#comment-6877 Amelia Fri, 04 Jun 2010 18:46:49 +0000 http://www.shsmaths.com/?page_id=1251#comment-6877 Hello, Sorry to interupt, but how did you get the 9? Amelia Hello,
Sorry to interupt, but how did you get the 9?
Amelia

]]>