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	<title>Comments on: A Level</title>
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		<title>By: Fiona</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1423</link>
		<dc:creator>Fiona</dc:creator>
		<pubDate>Tue, 03 Jun 2008 18:01:28 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1423</guid>
		<description>ah danka i thought it would be something quite obvious but i just couldn&#039;t click what</description>
		<content:encoded><![CDATA[<p>ah danka i thought it would be something quite obvious but i just couldn&#8217;t click what</p>
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		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1421</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Tue, 03 Jun 2008 15:57:45 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1421</guid>
		<description>Hi Fiona,

(1+3x)^-2 is the same thing as 1/(1+3x)^2

so all you need to do is to multiply your first 3 terms by x+4 and then tidy it up.

Tea Lady</description>
		<content:encoded><![CDATA[<p>Hi Fiona,</p>
<p>(1+3x)^-2 is the same thing as 1/(1+3x)^2</p>
<p>so all you need to do is to multiply your first 3 terms by x+4 and then tidy it up.</p>
<p>Tea Lady</p>
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	<item>
		<title>By: Fiona</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1422</link>
		<dc:creator>Fiona</dc:creator>
		<pubDate>Tue, 03 Jun 2008 14:19:59 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1422</guid>
		<description>mrs tibble i&#039;m doing the C4 practice paper 3 and i&#039;ve done the first part of qu 3 with no problems which was find the assecing powers of x up to an dincluding x^3 of (1+3x)^-2 , and the next part is to find the first three terms of x+4 / (1+ 3x)^2.

do i have to expand the top one using binomial expansion then multiply it by the answers i got for the bottom part or do i sub what i got for the bottom part as the x value in the top part??</description>
		<content:encoded><![CDATA[<p>mrs tibble i&#8217;m doing the C4 practice paper 3 and i&#8217;ve done the first part of qu 3 with no problems which was find the assecing powers of x up to an dincluding x^3 of (1+3x)^-2 , and the next part is to find the first three terms of x+4 / (1+ 3x)^2.</p>
<p>do i have to expand the top one using binomial expansion then multiply it by the answers i got for the bottom part or do i sub what i got for the bottom part as the x value in the top part??</p>
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	<item>
		<title>By: Emma Kitley</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1428</link>
		<dc:creator>Emma Kitley</dc:creator>
		<pubDate>Sun, 01 Jun 2008 21:49:52 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1428</guid>
		<description>Lol! I&#039;m a muppet!</description>
		<content:encoded><![CDATA[<p>Lol! I&#8217;m a muppet!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1427</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sun, 01 Jun 2008 21:44:29 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1427</guid>
		<description>Phew - that&#039;s a relief!!!</description>
		<content:encoded><![CDATA[<p>Phew &#8211; that&#8217;s a relief!!!</p>
]]></content:encoded>
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	<item>
		<title>By: Emma Kitley</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1426</link>
		<dc:creator>Emma Kitley</dc:creator>
		<pubDate>Sun, 01 Jun 2008 21:42:38 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1426</guid>
		<description>Yeah I was just looking at it and I realised I don&#039;t need to integrate it at all, sorry lol.</description>
		<content:encoded><![CDATA[<p>Yeah I was just looking at it and I realised I don&#8217;t need to integrate it at all, sorry lol.</p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1425</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sun, 01 Jun 2008 21:41:20 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1425</guid>
		<description>Why do you need to? What&#039;s the question?</description>
		<content:encoded><![CDATA[<p>Why do you need to? What&#8217;s the question?</p>
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	<item>
		<title>By: Emma Kitley</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1424</link>
		<dc:creator>Emma Kitley</dc:creator>
		<pubDate>Sun, 01 Jun 2008 21:26:14 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1424</guid>
		<description>How would you integrate the square root of (1.2^t -1) ?</description>
		<content:encoded><![CDATA[<p>How would you integrate the square root of (1.2^t -1) ?</p>
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	<item>
		<title>By: Emma Kitley</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1420</link>
		<dc:creator>Emma Kitley</dc:creator>
		<pubDate>Sat, 31 May 2008 12:52:52 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1420</guid>
		<description>Cool, thank you :-)</description>
		<content:encoded><![CDATA[<p>Cool, thank you <img src='http://www.shsmaths.com/wordpress/wp-includes/images/smilies/icon_smile.gif' alt=':-)' class='wp-smiley' /> </p>
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	<item>
		<title>By: Mrs Tibble</title>
		<link>http://www.shsmaths.com/revision/a-level/comment-page-11/#comment-1419</link>
		<dc:creator>Mrs Tibble</dc:creator>
		<pubDate>Sat, 31 May 2008 12:52:32 +0000</pubDate>
		<guid isPermaLink="false">http://shsmaths.wordpress.com/a-level/#comment-1419</guid>
		<description>The link Emma posted above also has January 08.</description>
		<content:encoded><![CDATA[<p>The link Emma posted above also has January 08.</p>
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